A) 2\[\Omega \]
B) 3\[\Omega \]
C) 4\[\Omega \]
D) 5\[\Omega \]
Correct Answer: C
Solution :
From balance condition of Wheatstone?s bridge there is no current passes through \[10\,\Omega \] resistor. Hence, equivalent resistance \[R=\frac{(4+4)\times (4+4)}{(4+4)+(4+4)}\] \[=\frac{8\times 8}{16}=4\,\Omega \]
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