A) \[M{{n}_{2}}{{O}_{7}}\]
B) \[Mn{{O}_{2}}\]
C) \[MnS{{O}_{4}}\]
D) \[M{{n}_{2}}{{O}_{3}}\]
Correct Answer: A
Solution :
When \[KMn{{O}_{4}}\] react with \[{{H}_{2}}S{{O}_{4}}\] (cone.) we get a highly explosive compound\[M{{n}_{2}}{{O}_{7}}\]. The following reaction take place. \[KMn{{O}_{4}}+{{H}_{2}}S{{O}_{4}}(conc.)\to \] \[\underset{\text{Green}\,\,\text{oily}}{\mathop{M{{n}_{2}}{{O}_{7}}}}\,+2KHS{{O}_{4}}+{{H}_{2}}O\]
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