A) \[{{H}_{2}}S{{O}_{4}}\] reduces\[HI\]to\[{{I}_{2}}\]
B) \[HI\] is of violet colour
C) \[HI\] gets oxidised to \[{{I}_{2}}\]
D) \[HI\] changes to\[HI{{O}_{3}}\]
Correct Answer: C
Solution :
\[HI\] being a stronger reducing agent than \[{{H}_{2}}S{{O}_{4}},\] reduces \[{{H}_{2}}S{{O}_{4}}\] to \[S{{O}_{2}}\] and is itself oxidized to\[{{I}_{2}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
