A) 14%
B) 28%
C) 56%
D) 68%
Correct Answer: C
Solution :
\[1\,M\]or \[10\,mL\]\[{{H}_{2}}S{{O}_{4}}=1M\]of \[20\,mL\,N{{H}_{3}}\] 1000 mL of 1 M ammonia contains = 14 g nitrogen 20 mL of \[1\,M\,N{{H}_{3}}\] contains \[=\frac{14\times 20}{1000}g\]nitrogen % age of nitrogen \[=\frac{14\times 20\times 100}{1000\times 0.5}=56.0\,%\]
You need to login to perform this action.
You will be redirected in
3 sec
