A) 4.125%
B) 3.125%
C) 31.1%
D) 42.125%
Correct Answer: B
Solution :
From, Radioactive decay \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] Per cent of remaining quantity, when n = 5 \[\frac{N}{{{N}_{0}}}\times 100={{\left( \frac{1}{2} \right)}^{5}}\times 100\] \[=\frac{1}{32}\times 100=3.125%.\]
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