A) - 0.5 J
B) - 1.25 J
C) 1.25 J
D) 0.5 J
Correct Answer: B
Solution :
Work done by the particle \[W=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times \frac{100}{1000}\times {{(5)}^{2}}=-1.25\,J\] {As the motion of particle in opposite direction of applied for force.}
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