A) \[{{\lambda }_{ph}}>{{\lambda }_{e}}\]
B) \[{{\lambda }_{ph}}<{{\lambda }_{e}}\]
C) \[{{\lambda }_{ph}}={{\lambda }_{e}}\]
D) \[\frac{{{\lambda }_{e}}}{{{\lambda }_{ph}}}=\text{constant}\]
Correct Answer: A
Solution :
Wavelength\[(\lambda )\propto \frac{\text{1}}{\text{mass}\,\text{(m)}}\] As mass of photon is less than that of electron, hence, wavelength of photon is greater than that of electron.
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