A) \[CaB{{r}_{2}}\]
B) \[Ca{{I}_{2}}\]
C) \[Ca{{F}_{2}}\]
D) \[CaC{{l}_{2}}\]
Correct Answer: B
Solution :
As we go from top to bottom in a group melting point is decreases, so, calcium iodine \[(Ca{{I}_{2}})\]has lowest melting point.
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