A) \[ns\xrightarrow{{}}(n-1)d\xrightarrow{{}}(n-2)f\xrightarrow{{}}np\]
B) \[ns\xrightarrow{{}}(n-2)f\xrightarrow{{}}np\xrightarrow{{}}(n-1)d\]
C) \[ns\xrightarrow{{}}np\xrightarrow{{}}(n-1)d\xrightarrow{{}}(n-2)f\]
D) \[ns\xrightarrow{{}}(n-2)f\xrightarrow{{}}(n-1)d\xrightarrow{{}}np\]
Correct Answer: D
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