A) \[XeO{{F}_{4}}\] is formed
B) \[Xe{{O}_{2}}{{F}_{2}}\] is formed
C) It is a redox reaction
D) \[Xe{{O}_{3}}\]is formed
Correct Answer: C
Solution :
Hydrolysis of \[Xe{{F}_{6}}\] is not a redox reaction. \[Xe{{F}_{6}}\] reacts violently with water, but slow hydrolysis by atmospheric moisture gives highly explosive solid,\[Xe{{O}_{3}}\]. \[Xe{{F}_{6(s)}}+3{{H}_{2}}{{O}_{(l)}}\to Xe{{O}_{3(s)}}+6H{{F}_{(aq)}}\] Partial hydrolysis of \[Xe{{F}_{6}}\] yields \[XeO{{F}_{4}}\] and\[Xe{{O}_{2}}{{F}_{2}}.\] \[Xe{{F}_{6}}+{{H}_{2}}O\to XeO{{F}_{4}}+2HF\] \[Xe{{F}_{6}}+2{{H}_{2}}O\to Xe{{O}_{2}}{{F}_{2}}+4HF\]
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