A) 200 V, 50 Hz
B) 200 V, 500 Hz
C) 2 V, 50 Hz
D) 2 V, 5 Hz
Correct Answer: A
Solution :
Given: Turns on primary winding = 500; Turns on secondary winding = 5000; Primary winding voltage \[({{E}_{p}})=20V\]and frequency = 50 Hz. We know that \[\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{E}_{s}}}{{{E}_{p}}}\]or\[\frac{5000}{500}=\frac{{{E}_{s}}}{20}\]or \[{{E}_{S}}=\frac{5000\times 20}{500}=200\,V\]and frequency remains the same. Therefore secondary winding will have an output of 200 V, 50 Hz.
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