JIPMER Jipmer Medical Solved Paper-2015

  • question_answer
    A diatomic gas initially at \[18{}^\circ C\] is compressed adiabatically to one eighth of its original volume. The temperature after compression will be:

    A)  \[18{}^\circ \,C\]            

    B)         \[887.4{}^\circ \,C\]

    C)  \[395.4{}^\circ \,C\]         

    D)         \[144{}^\circ \,C\]

    Correct Answer: C

    Solution :

    Given: Initial temperature \[({{T}_{1}})=18{}^\circ C\]\[=(273+18)=291K\]and\[{{V}_{2}}=1\text{/}8\,\,{{V}_{1}}.\] We know that for adiabatic compression, \[T{{V}^{\gamma -1}}=\text{Constant}\] or            \[{{T}_{1}}{{V}_{1}}^{\gamma -1}={{T}_{2}}V_{2}^{\gamma -1}\] Therefore\[{{T}_{2}}={{T}_{1}}{{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}=291\times {{(8)}^{1.4-1}}\] \[=291\times {{(8)}^{0.4}}=291\times 2.297\] \[=668.4\,K.\] \[=395.4{}^\circ \,C\]


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