JIPMER Jipmer Medical Solved Paper-2015

  • question_answer
    Complete the equation for the following fission process: \[{}_{92}{{U}^{235}}+{}_{0}{{n}^{1}}\to {}_{38}S{{r}^{90}}+....\]

    A)  \[{}_{57}X{{e}^{142}}\]

    B)         \[{}_{54}X{{e}^{145}}\]

    C)  \[{}_{54}X{{e}^{143}}+3{}_{0}{{n}^{1}}\]

    D)         \[{}_{54}X{{e}^{141}}+{}_{0}{{n}^{1}}\]

    Correct Answer: C

    Solution :

    Comparing both sides of the given fission reaction, we get\[{}_{92}{{U}^{235}}+{}_{0}{{n}^{1}}\to {}_{38}S{{r}^{90}}+{}_{54}X{{e}^{143}}\]\[+3{}_{0}{{n}^{1}}.\] Therefore the equation is balanced and option C is correct.


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