A) 3 : 1
B) 1 : 3
C) 1 : 2
D) 2 : 1
Correct Answer: B
Solution :
Given: Mass (m) = 1 kg; Upward acceleration \[({{a}_{1}})=4.9\,m\text{/}{{s}^{2}}\] and downward acceleration \[({{a}_{2}})=4.9\,m\text{/}{{s}^{2}}\]. We know that when body is moving upward then tension\[({{T}_{1}})=m\,(g-a)\]\[=1\,(9.8-4.9)=4.9N\]and when the body is moving downward a the tension\[({{T}_{2}})=m(a+g)\]\[=1\,(4.9+9.8)=14.7\,N.\] Therefore, \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{4.9}{14.7}=\frac{1}{3}\] or \[{{T}_{1}}:{{T}_{2}}=1:3.\]
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