question_answer

If a compound, on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is:

A)  \[{{C}_{2}}{{H}_{2}}OCl\]                            

B)     \[C{{H}_{2}}ClO\]           

C)     \[CHClO\]                          

D)     \[ClC{{H}_{2}}O\]