A) \[1.576\times {{10}^{4}}\]
B) \[1.576\times {{10}^{3}}\]
C) \[15.76\]
D) \[2.136\times {{10}^{4}}\]
Correct Answer: A
Solution :
The enzyme must contain at least one atom of Se. \[\because \] 0.5 g of Se is present in 100 g of enzyme \[\therefore \] \[78.4\,g\]of Se will be present in\[=\frac{100\times 78.4}{0.5}\] \[=1.576\times {{10}^{4}}\,g\]of enzymes.
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