A) \[\Delta x\ge 1\,\,\times \,\,{{10}^{-35}}m\]
B) \[\Delta x\ge 2\,\,\times \,\,{{10}^{-37}}m\]
C) \[\Delta x\ge 2\,\,\times \,\,{{10}^{-36}}m\]
D) \[\Delta x\ge 4\,\,\times \,\,{{10}^{-38}}m\]
Correct Answer: B
Solution :
\[\Delta x\ge \frac{h}{(4\pi )(m\Delta v)}\] \[\Delta x\ge \frac{6.626\,\times {{10}^{-34}}}{\left( 4\times 3.14\,\times 1050 \right)\left( 0.9 \right)\,\left( \frac{1}{3600} \right)\,\left( \frac{1000}{1} \right)}\] \[\Delta x\ge 2\times {{10}^{-37}}m\] The uncertainty in the position of the car is far smaller than the uncertainty in the position of an electron in a hydrogen atom \[(3\times {{10}^{-10}}m)\] and far too small a value to have any measurable consequences.
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