A) 12%
B) 10%
C) 8%
D) 2%
Correct Answer: C
Solution :
Given: Percentage error in mass = 2%\[=\frac{2}{100}\] and percentage error in speed = 3% =\[\frac{3}{100}\]. We know that error in measurement of kinetic energy \[\frac{\Delta \,K.E.}{K.E.}=\frac{1}{2}m{{v}^{2}}\] \[=\frac{\Delta m}{m}+{{\left( \frac{\Delta v}{v} \right)}^{2}}=\frac{\Delta m}{m}+2\times \frac{\Delta v}{v}\] \[=\frac{2}{100}+2\times \frac{3}{100}=\frac{8}{100}=8%\]
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