Solved papers for JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

done JEE Main Paper (Held On 11 April 2014) Total Questions - 2

• question_answer1) An electromagnetic wave of frequency \[1\times {{10}^{14}}\]hertz is propagating along z-axis. The amplitude of electric field is 4 V/m. If \[{{\varepsilon }_{0}}=8.8\times {{10}^{-12}}{{C}^{2}}/N-{{m}^{2}},\]then average energy density of electric field will be:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )
  A)
  \[35.2\times {{10}^{-10}}J/{{m}^{3}}\]   
  done clear
  B)
  \[35.2\times {{10}^{-11}}J/{{m}^{3}}\]
  done clear
  C)
  \[35.2\times {{10}^{-12}}J/{{m}^{3}}\]   
  done clear
  D)
  \[35.2\times {{10}^{-13}}J/{{m}^{3}}\]
  done clear
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• question_answer2) Match the List-I (Phenomenon associated with electromagnetic radiation) with List-II (Part of electromagnetic spectrum) and select the correct code from the choices given below this lists:

  (I) Doublet of sodium	(a) Visible radiation
  (II) Wavelength corresponding to temperature associated with the isotropic radiation filling all space	(b) Microwave
  (III) Wavelength emitted by Atomic hydrogen in Interstellar space	(c) Short radio wave
  (IV) Wavelength of radiation arising from two close energy levels in hydrogen	(d) X-rays

    [JEE Main Online Paper ( Held On 11 Apirl  2014 )
  A)
  (I)-(A), (II)-(B), (III)-(B), (IV)-(C)
  done clear
  B)
  (I)-(A), (II)-(B), (III)-(C), (IV)-(C)
  done clear
  C)
  (I)-(D), (II)-(C), (III)-(A), (IV)-(B)
  done clear
  D)
  (I)-(B), (II)-(A), (III)-(D), (IV)-(A)
  done clear
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