Manipal Engineering Manipal Engineering Solved Paper-2008

  • question_answer
    The equivalent resistance between points A and B of an infinite network of resistance s each of \[1\,\Omega ,\] connected as shown, is

    A)  infinite                                

    B)  2\[\Omega \]

    C)  \[\frac{1+\sqrt{5}}{2}\Omega \]              

    D)         zero

    Correct Answer: C

    Solution :

    Let\[x\]be the equivalent resistance of entire network between\[A\]and\[B\]. Hence, we have \[{{R}_{AB}}=1+\]resistance of parallel combination of\[1\Omega \]and\[x\Omega \] \[\therefore \]  \[{{R}_{AB}}=1+\frac{x}{1+x}\] \[\therefore \]  \[x=1+\frac{x}{1+x}\] \[\Rightarrow \]               \[x+{{x}^{2}}=1+x+x\] \[\Rightarrow \]               \[{{x}^{2}}-x-1=0\] \[\Rightarrow \]               \[x=\frac{1+\sqrt{1+4}}{2}=\frac{1+\sqrt{5}}{2}\Omega \]


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