A) 100 m/s
B) 10 m/s
C) 1m/s
D) \[10\sqrt{10}\]m/s
Correct Answer: B
Solution :
Bernoullis theorem for unit mass of liquid\[\frac{p}{\rho }+\frac{1}{2}{{v}^{2}}=\]constant As the liquid starts flowing, it pressure energy decreases \[\frac{1}{2}{{v}^{2}}=\frac{{{p}_{1}}-{{p}_{2}}}{\rho }\Rightarrow \frac{1}{2}{{v}^{2}}=\frac{3.5\times {{10}^{5}}-3\times {{10}^{5}}}{{{10}^{3}}}\] \[\Rightarrow \,\,{{v}^{2}}=\frac{2\times 0.5\,\times {{10}^{5}}}{{{10}^{3}}}\,\Rightarrow \,{{v}^{2}}=100\] \[\Rightarrow \,\,v=10\,m/s\]
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