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Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    5 moles of\[S{{O}_{2}}\]and 5 moles of\[{{O}_{2}}\]are allowed to react. At equilibrium, it was found that 60% of\[S{{O}_{2}}\]is used up. If the partial pressure of the equilibrium mixture is one atmosphere, the partial pressure of\[{{O}_{2}}\]is

    A) \[0.82\,\,atm\]

    B)                                        \[0.52\,\,atm\]

    C)        \[0.21\,\,atm\]                 

    D)        \[0.41\,\,atm\]

    Correct Answer: D

    Solution :

                             \[2S{{O}_{2}}(g)+{{O}_{2}}(g)2S{{O}_{3}}(g)\] Initial                     5               5                     0 At Equilibrium      (5 - 3)     (5 - 1.5)         3                                 = 2          = 3.5                                 \[\therefore \,\,\,\,\,\,\,p{{O}_{2}}=\frac{3.5\times 1}{8.5}\,=0.41\,atm\]


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