A) 2
B) 1
C) 0
D) \[-\frac{1}{2}\]
Correct Answer: D
Solution :
\[\frac{1}{{{(x-1)}^{2}}(x-2)}=\frac{1}{-2{{(1-x)}^{2}}\left( 1-\frac{x}{2} \right)}\] \[=-\frac{1}{2}\left[ {{(1-x)}^{2}}{{\left( 1-\frac{x}{2} \right)}^{-1}} \right]\] \[=-\frac{1}{2}\left[ (1+2x+...)\left( 1+\frac{x}{2}+... \right) \right]\] \[\therefore \]Coefficient of constant term is\[-\frac{1}{2}\].
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