A) \[4\pi \]
B) \[3\pi \]
C) \[2\pi \]
D) \[\pi \]
Correct Answer: D
Solution :
Since, given lines are parallel. \[\therefore \] \[d=\frac{15-5}{\sqrt{{{4}^{2}}+{{3}^{2}}}}=\frac{10}{5}\] \[\Rightarrow \] \[d=2=\]diameter of the circle \[\therefore \]Radius of circle\[=1\] \[\therefore \]Area of circle\[=\pi {{r}^{2}}=\pi \]sq unit
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