question_answer

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

A)  225 J                                    

B)  200 J

C)  400 J                    

D)         175 J

Correct Answer: B

Solution :

Word done\[W=\]Area\[ABCEFDA\] = Area ABCD + Area\[CEFD\]                 \[=\frac{1}{2}\times (15+10)\times 10+\frac{1}{2}\times (10+20)\times 5\]                 \[=125+75=200\,\,J\]