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Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    The electric potential at any point x, y, z in metres is given by\[V=3{{x}^{2}}.\]. The electric field at a point (2. 0, 1) is

    A)  \[12\,V{{m}^{-1}}\]                                       

    B)  \[-6\,V{{m}^{-1}}\]

    C)  \[6\,V{{m}^{-1}}\]         

    D)         \[-12\,V{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    Here, electric potential                 \[V=3{{x}^{2}}\] Electric field,                 \[E=\frac{\partial V}{\partial x}=-\frac{\partial }{\partial x}(3{{x}^{2}})=-6x\] \[\therefore \]  \[{{E}_{(2,\,\,0,\,\,1)}}=-12\,\,V{{m}^{-1}}\]


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