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Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    An aqueous solution containing\[\text{6}\text{.5}\,\,\text{g}\]of\[NaCl\]of\[90%\]purity was subjected to electrolysis. After the complete electrolysis, the solution was evaporated to get solid\[NaOH\]. The volume of\[1\,\,M\]acetic acid required to neutralize\[NaOH\]obtained above is

    A) \[1000\,\,c{{m}^{3}}\]                   

    B) \[2000\,\,c{{m}^{3}}\]

    C) \[100\,\,c{{m}^{3}}\]     

    D)        \[200\,\,c{{m}^{3}}\]

    Correct Answer: C

    Solution :

    Weight of pure\[NaCl=6.5\times 0.9=5.85\,\,g\] No. of equivalence of\[NaCl=\frac{5.85}{58.5}=0.1\] No. of equivalence of\[NaOH\]obtained\[=0.1\] Volume of 1 M acetic acid required for the neutralization of\[NaOH=\frac{0.1\times 1000}{1}\]                                               \[=100\,\,c{{m}^{3}}\]


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