A) \[\sigma 2s\]and\[\sigma 1s\]
B) \[\pi 2{{p}_{x}}\]and\[\pi 2{{p}_{y}}\]
C) \[\pi 2{{p}_{x}}\]and\[\sigma 2{{p}_{z}}\]
D) \[\sigma 2{{p}_{z}}\]and\[\pi 2{{p}_{x}}\]
Correct Answer: B
Solution :
\[\pi 2{{p}_{x}}\]and\[\pi 2{{p}_{y}}\]or\[\pi 2{{p}_{x}}\]and\[\pi 2{{p}_{y}}\]orbitals have nearly equal energy and thus, are called degenerate orbitals.
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