A) \[[M{{L}^{-1}}T]\]
B) \[[M{{L}^{-1}}{{T}^{0}}]\]
C) \[[ML{{T}^{0}}]\]
D) \[[{{M}^{0}}L{{T}^{-1}}]\]
Correct Answer: B
Solution :
As\[F\propto {{v}^{2}}\] or \[F=k{{v}^{2}}\] \[\therefore \] \[k=\frac{F}{{{v}^{2}}}\] \[[k]=\frac{[F]}{[{{v}^{2}}]}=\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}{{T}^{-2}}]}\] \[=[M{{L}^{-1}}{{T}^{0}}]\]
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