A) 12V
B) 2.4V
C) 24V
D) 36V
Correct Answer: C
Solution :
As\[3\Omega \]and\[6\Omega \]resistances are in parallel their equivalent resistance will be\[2\Omega \]. Here\[2\Omega \]and \[4\Omega \]are in series, their equivalent resistance will be\[6\Omega \]. From current distribution law \[{{i}_{1}}=\frac{12\times 18}{18}=12\,\,A\] \[{{i}_{2}}=\frac{6\times 18}{18}=6A\] Now\[12\,\,A\]current is entering in parallel combination of\[3\Omega \]and\[6\Omega \]again from current distribution law \[i_{1}^{}=\frac{6\times 12}{9}=8\,\,A\] \[i_{2}^{}=\frac{3\times 12}{9}=4\,\,A\] \[\therefore \]Potential difference across \[3\Omega \] resistance \[=8\times 3=24\,\,V\]You need to login to perform this action.
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