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Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    A body of mass 10 kg is moving with a constant velocity of 10 m/s. When a constant force acts for 4 s on it, it moves with a velocity 2 m/s in the opposite direction. The acceleration produced in it is

    A)  \[3\,m/{{s}^{2}}\]                          

    B)  \[-3\,m/{{s}^{2}}\]

    C)  \[0.3\,m/{{s}^{2}}\]                      

    D)         \[0.03\,m/{{s}^{2}}\]

    Correct Answer: B

    Solution :

    According to equation of motion                 \[v=u+at\] \[\Rightarrow \]               \[-2=10+a\times 4\] \[\therefore \]  \[a=-3\,\,m/{{s}^{2}}\]


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