Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    A disc of radius 0.1 m is rotating with a frequency 10 rev/s in a normal magnetic field of strength 0.1 T. Net induced emf is

    A) \[2\pi \times {{10}^{-2}}v\]                         

    B)  \[\pi \times {{10}^{-2}}v\]

    C)  \[\frac{\pi }{2}{{10}^{-2}}V\]                     

    D)         None of these

    Correct Answer: B

    Solution :

    Net induced emf due to disc is                 \[\varepsilon =\frac{1}{2}B\omega {{l}^{2}}\]                 \[=\frac{1}{2}\times 0.1\times 2\pi \times 10\times 0.1\times 0.1\]                 \[=\pi \times {{10}^{-2}}V\]


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