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Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    Current in a coil changes from 5 A to 10 A in 0.2 s. If the coefficient of self-induction is 10 H, then the inducedi emf is

    A)  112 V                                   

    B)  250 V

    C)  125 V                   

    D)         230 V

    Correct Answer: B

    Solution :

    Induced emf in the coil is given by                 \[e=\frac{Ldi}{dt}\] or            \[e=10\times \frac{(10-5)}{0.2}\]                 \[\Rightarrow \]\[e=250\,\,V\] 


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