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Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
     In Youngs double slit experiment, slit separation is 0.6 mm and the separation between slit and screen is 1.2 m. The angular width is (the wavelength of light used is \[4800\overset{\text{o}}{\mathop{\text{A}}}\,\])

    A)  30 rad                                  

    B)  \[8\times {{10}^{-4}}\] rad

    C)  12 rad                  

    D)         70.5 rad

    Correct Answer: B

    Solution :

    Angular width\[\theta =\frac{\beta }{D}\]                 \[=\frac{\lambda }{d}=\frac{4800\times {{10}^{-10}}}{0.6\times {{10}^{-3}}}\]                 \[=8\times {{10}^{-4}}\,\,rad\]


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