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Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    X-ray of wavelength \[\lambda =2\overset{0}{\mathop{A}}\,\]is emitted from the metal target. The potential difference applied across the cathode and the metal target is

    A)  5525 V                                 

    B)  320 V

    C)  6200 V                 

    D)         3250 V

    Correct Answer: C

    Solution :

    Potential difference\[V=\frac{hc}{e\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 2\times {{10}^{-10}}}\] = 6200 volt


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