A) azobenzene
B) hydrazobenzene
C) N-phenyl hydroxyl amine
D) aniline
Correct Answer: D
Solution :
Reduction of nitrobenzene by\[Zn\]and\[N{{H}_{4}}Cl\]gives N-phenyl hydroxylamine.
(\[\because \]In the product,\[-Br\] is para to\[-C{{H}_{3}}\]and meta to\[-COOH\].)
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