A) \[F{{e}_{2}}{{O}_{3}}\,\,melt\]
B) \[FeO\]
C) \[F{{e}_{3}}{{O}_{4}}\]
D) metallic iron
Correct Answer: D
Solution :
On igniting at\[{{1400}^{o}}C\],\[F{{e}_{2}}{{O}_{3}}\]get reduced to metallic\[Fe\]. \[3F{{e}_{2}}{{O}_{3}}+CO\xrightarrow{{}}2F{{e}_{3}}{{O}_{4}}+C{{O}_{2}}\] \[F{{e}_{3}}{{O}_{4}}+CO\xrightarrow{{}}3FeO+C{{O}_{2}}\] \[FeO+CO\xrightarrow{{}}Fe+C{{O}_{2}}\]
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