Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    \[\int{\frac{{{x}^{2}}}{({{x}^{2}}+2)({{x}^{2}}+3)}dx}\]is equal to

    A) \[-\sqrt{2}{{\tan }^{-1}}\left( \frac{x}{\sqrt{2}} \right)+\sqrt{3}{{\tan }^{-1}}\left( \frac{x}{\sqrt{3}} \right)+C\]

    B) \[\sqrt{2}{{\tan }^{-1}}\left( \frac{x}{\sqrt{2}} \right)+\sqrt{3}{{\tan }^{-1}}\left( \frac{x}{\sqrt{3}} \right)+C\]

    C) \[-\sqrt{2}{{\tan }^{-1}}x+\sqrt{3}{{\tan }^{-1}}x+C\]

    D)  None of the above

    Correct Answer: A

    Solution :

    \[\int{\frac{{{x}^{2}}}{({{x}^{2}}+2)({{x}^{2}}+3)}dx=\int{\left( \frac{3}{{{x}^{2}}+3}-\frac{2}{{{x}^{2}}+2} \right)dx}}\] \[=\frac{3}{\sqrt{3}}{{\tan }^{-1}}\left( \frac{x}{\sqrt{3}} \right)-\frac{2}{\sqrt{2}}{{\tan }^{-1}}\left( \frac{x}{\sqrt{2}} \right)+C\] \[=\sqrt{3}{{\tan }^{-1}}\left( \frac{x}{\sqrt{3}} \right)-\sqrt{2}{{\tan }^{-1}}\left( \frac{x}{\sqrt{2}} \right)+C\]


You need to login to perform this action.
You will be redirected in 3 sec spinner