A) \[-1/10\]
B) \[1/10\]
C) \[-1/8\]
D) None of these
Correct Answer: A
Solution :
\[\underset{x\to 1}{\mathop{\lim }}\,\frac{(2x-3)(\sqrt{x}-1)}{2{{x}^{2}}+x-3}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{(2x-3)(\sqrt{x}-1)}{(2x+3)(x-1)}\] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{(2x-3)}{(2x+3)(\sqrt{x}+1)}\] \[=\frac{2-3}{(2+3)(\sqrt{1}+1)}=\frac{1}{10}\]
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