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Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    If\[\frac{{{e}^{x}}+2}{({{e}^{x}}-1)(2{{e}^{x}}-3)}=-\frac{3}{{{e}^{x}}-1}+\frac{B}{2{{e}^{x}}-3}\]then\[B\]is equal to

    A)  1                                            

    B)  3

    C)  5                            

    D)         7

    Correct Answer: D

    Solution :

    Here,\[{{e}^{x}}+2=-3(2{{e}^{x}}-3)+B({{e}^{x}}-1)\] On equating the coefficient of\[{{e}^{x}}\]and constant, we get                 \[1=-6+B\]                 \[2=9-B\Rightarrow B=7\]


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