A) \[(-\infty ,\,\,\infty )\]
B) \[(-\infty ,\,\,0)\cup (0,\,\,\infty )\]
C) \[(0,\,\,\infty )\]
D) \[[0,\,\,\infty )\]
Correct Answer: A
Solution :
Given that, \[f(x)=x|x|\] \[\therefore \] \[f(x)=\left\{ \begin{matrix} {{x}^{2}}, & x\ge 0 \\ -{{x}^{2}}, & x<0 \\ \end{matrix} \right.\] It is clear from the graph that\[f(x)\]is differentiable everywhere.You need to login to perform this action.
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