A) 0.5 s
B) 1.0 s
C) 2.0 s
D) 3.14 s
Correct Answer: D
Solution :
Acceleration\[a={{\omega }^{2}}y\] \[a={{\left( \frac{2\pi }{T} \right)}^{2}}y\] \[\Rightarrow \] \[{{T}^{2}}=\frac{4{{\pi }^{2}}y}{a}\] \[\Rightarrow \] \[T=2\pi \sqrt{\frac{y}{a}}\] \[=2\pi \sqrt{\frac{3}{12}}\] \[T=2\pi \times \frac{1}{2}=3.14\,\,s\]
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