A) \[2{}^\circ C/cm\]
B) \[2{}^\circ C/m\]
C) \[20{}^\circ C/cm\]
D) \[{{20}^{o}}C/m\]
Correct Answer: A
Solution :
Temperature gradient of the rod \[\frac{\Delta \theta }{\Delta x}=\frac{{{\theta }_{2}}-{{\theta }_{1}}}{l}\] \[\therefore \] \[\frac{\Delta \theta }{\Delta x}=\frac{125-25}{50}\] \[=\frac{100}{50}={{2}^{o}}\,\,C/cm\]
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