Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    A p-type semiconductor has acceptor levels 57 meV above the valence band. The maximum wavelength of light required to create a hole

    A) \[57\overset{0}{\mathop{A}}\,\]            

    B)         \[57\times {{10}^{-3}}\overset{0}{\mathop{A}}\,\]

    C)  \[217105\overset{0}{\mathop{A}}\,\]        

    D)         \[11.61\times {{10}^{-33}}\overset{0}{\mathop{A}}\,\]

    Correct Answer: C

    Solution :

    \[E=57\,\,meV=57\times {{10}^{-3}}eV\] \[\therefore \]  \[\lambda =\frac{12375}{E}=\frac{12375}{57\times {{10}^{-3}}}\]                 \[=217.105\times {{10}^{3}}\overset{\text{o}}{\mathop{\text{A}}}\,\]                 \[\lambda =217105\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]


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