A) \[36\,\,g\]of water
B) \[28\,\,g\]of\[C{{O}_{2}}\]
C) \[46\,\,g\]of\[C{{H}_{3}}OH\]
D) \[58\,\,g\]of\[{{N}_{2}}{{O}_{5}}\]
Correct Answer: A
Solution :
\[36\,\,g\]of water\[=\frac{36}{18}=2\,\,mol\] \[28\,\,g\]of\[C{{O}_{2}}=\frac{28}{44}=0.64\,\,mol\] \[46\,\,g\]of\[C{{H}_{3}}OH=\frac{46}{32}=1.44\,\,mol\] \[58\,\,g\]of\[{{N}_{2}}{{O}_{5}}=\frac{58}{108}=0.54\,\,mol\]
You need to login to perform this action.
You will be redirected in
3 sec
