A) 2 BM
B) 5.9 BM
C) 7BM
D) 35 BM
Correct Answer: B
Solution :
No. of unpaired electrons in\[Fe=5\] Magnetic moment,\[\mu =\sqrt{n(n+2)}=\sqrt{5(5+2)}\] \[-\sqrt{35}=5.92\,\,BM\]
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