• # question_answer For a particle executing simple harmonic motion, the kinetic energy$K$is given by$K={{K}_{0}}{{\cos }^{2}}\omega t$. The maximum value of potential energy is A) ${{K}_{0}}$                                       B)  zero C) ${{K}_{0}}/2$   D)         not obtainable

${{K}_{\max }}={{K}_{0}}=$total energy As total energy remains conserved in$SHM$, hence when$U$is maximum in$SHM$,$K=0$, i.e.,$E$is also equal to${{U}_{\max }},\,\,i.e.,\,\,{{U}_{\max }}=E={{K}_{0}}$.