A) \[x=-1\]
B) \[x=1\]
C) \[x=-\frac{3}{2}\]
D) \[x=\frac{3}{2}\]
Correct Answer: D
Solution :
We have,\[{{y}^{2}}+4y+4x+2=0\] \[\Rightarrow \] \[{{(y+2)}^{2}}+4x-2=0\] \[\Rightarrow \] \[{{(y+2)}^{2}}=-4\left( x-\frac{1}{2} \right)\] Replace, \[y+2=Y,\,\,x-\frac{1}{2}=X\] We have, \[{{Y}^{2}}=-4X\] This is a parabola with directrix at\[X=1\] \[\Rightarrow \] \[x-\frac{1}{2}=1\] \[\Rightarrow \] \[x=\frac{3}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
