A) \[250\,\,K\]
B) \[{{250}^{o}}C\]
C) \[2500\,\,K\]
D) \[{{25}^{o}}C\]
Correct Answer: A
Solution :
\[\frac{pV}{T}=\]constant;\[V=\]constant \[\therefore \] \[\frac{p}{T}=\text{constant}\] \[\therefore \] \[\frac{p}{T}=\frac{100.4p}{1000}\times \frac{1}{(T+1)}\] \[\frac{1}{T}=\frac{100.4}{100}\times \frac{1}{(T+1)}\] \[\frac{1}{T}=\frac{100.4}{100T+100}\] \[T=250\,\,K\]
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