Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    A man and a woman appears in an interview for two vacancies in the same post. The probability of mans selection is\[\frac{1}{4}\]and that of the womans selection is\[\frac{1}{3}\]. What is the probability that none of them will be selected?

    A) \[\frac{1}{2}\]                                   

    B) \[\frac{1}{12}\]

    C) \[\frac{1}{4}\]                   

    D)         None of these

    Correct Answer: A

    Solution :

    Let\[{{E}_{1}}\]be the events that man will be selected and\[{{E}_{2}}\]the events that woman will be selected Then,    \[P({{E}_{1}})=\frac{1}{4}\] So,          \[P({{\bar{E}}_{1}})=1-\frac{1}{4}=\frac{3}{4}\] and        \[P({{E}_{2}})=\frac{1}{3}\] \[\Rightarrow \]               \[P({{\bar{E}}_{2}})=\frac{2}{3}\] \[\therefore \]\[{{E}_{1}}\]and\[{{E}_{2}}\]are independent events.       \[P({{\bar{E}}_{1}}\cap {{\bar{E}}_{2}})=P({{\bar{E}}_{1}})\times P({{\bar{E}}_{2}})\]                            \[=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}\]


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